5a^2+40a+80=0

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Solution for 5a^2+40a+80=0 equation: 



5a^2+40a+80=0

a = 5; b = 40; c = +80;
Δ = b2-4ac
Δ = 402-4·5·80
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{-40}{10}=-4$

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